4.9t^2-3t=5

Solution for 4.9t^2-3t=5 equation:

4.9t^2-3t=5

We move all terms to the left:

4.9t^2-3t-(5)=0

a = 4.9; b = -3; c = -5;
Δ = b2-4ac
Δ = -32-4·4.9·(-5)
Δ = 107
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{107}}{2*4.9}=\frac{3-\sqrt{107}}{9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{107}}{2*4.9}=\frac{3+\sqrt{107}}{9.8}
$